3:34 a.m. (Henry Bins Book 4)

3:34 a.m. (Henry Bins Book 4)

Matematika 3^15×27^10=9^n
maka nilai n adalah

3^15×27^10=9^n
maka nilai n adalah

[tex] \tt {3}^{15} \times {27}^{10} = {9}^{n} [/tex]

[tex] \tt {3}^{15} \times {( {3}^{3} )}^{10} = {( {3}^{2} )}^{n} [/tex]

[tex] \tt {3}^{15} \times {3}^{30} = {3}^{2n} [/tex]

[tex] \tt {3}^{(15 + 30)} = {3}^{2n} [/tex]

[tex] \tt {3}^{45} = {3}^{2n} [/tex]

45 = 2n

n = 45/2

n = 22½

[tex] \pink{\boxed{\red{\boxed{\purple{\mathfrak{\ast ~ \blue{Celia ~ Claire} ~ \ast}}}}}}[/tex]

[tex]\tt 3^{15}\times 27^{10}=9^n\\\\3^{15}\times 3^{10\times 3}=3^{2n}\\\\3^{15+30}=3^{2n}\\\\n = \frac{45}{2}\\ \\~~= 22\frac{1}{2}[/tex]

Jadi, nilai n adalah 22 ¹/₂

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